Are you all ready for the year ahead? I know I am. And what better way to start things off than our yearly math puzzle to ring in the new year 2023. Yes, that’s right – a math puzzle. This one can be solved by anyone with a little logic and problem-solving skills. Ready to give it a try? Then, let’s get started.
MATH PUZZLE FOR NEW YEAR 2023
We have two math puzzles this year where we use the number 2023 as the math number.
1. WHAT IS a MATHEMATICAL equation that EQUALS 2023 ?
Can you create a mathematical equation that yields the number 2023 using only the digits 9, 8, 7, 6, 5, 4, 3, 2 and 1 in that order? Only the four basic mathematical operators can be used (addition, subtraction, multiplication, and division). Additionally, you are free to use as many parenthesis as you want. But, each digit can be used once only.
Did you solve it ? Click below to find the solution.
One way to solve the equation is
((( 9x8x7) +2 ) x 4 ) – ( 5+3) + ( 6 + 1 )
Can you find other solutions, let us know in the comments below.
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2. YEARLY MATH PUZZLE 2023
Since the past couple of years, we have been doing our yearly math puzzle. The challenge is to create an equation for all the numbers from 1 to 20 using only the digits of the current year, 2023.
For example, we can write the digit 1 as 2 + 0 + 2 – 3 , similarly we can write the digit 2 as 2 + (2 + 3 ) x 0 and so on
There are certain rules to follow
- You can only use the digits 2, 0, 2, 3.
- The expression must contain all four digits.
- The four digits can be used in the expression in any order.
- The operators +, -, x, /, (raised to a power), factorial, square root, and parentheses are all valid.
Here is a solution for the first 20 numbers.
1 = 2 + 0 + 2 – 3
2 = 2 + ( 2 + 3 ) x 0
3 = 2 + 0 + 3 – 2
4 = 2 + 2 + ( 3 x 0 )
5 = ( 2 x 0 ) + 2 + 3
6 = ( 2 x 0 ) + ( 2 x 3 )
7 = 2 + 0 + 2 + 3
8 = 2 + 0! + 2 + 3
9 = 2 + 0! + ( 2 x 3 )
10 = 3! + ( 2 x 2 ) + 0
11 = ( 2 + 0! )! + 2 + 3
12 = ( 2 + 0! )! + 2 x 3
13 = ( 3 x 2 x 2 ) + 1
14 = 3! + ( 2 + 0! )! + 2
15 = 3^2 + ( 2 + 0!)!
16 = ( 2^3 x 2 ) + 0
17 = ( 2^3 x 2 ) + 0!
18 = ( 3^2 x 2 ) + 0
19 = ( 3^2 x 2 ) + 0!
20 =(3+ 0!)! – (2^2)
You can further extend this activity to write expressions for numbers between 1 – 100 using digits 2,0,2 and 3.
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Beginning of the year 2023 Math PuzzlE WORKSHEET
These puzzle can be a great brainteaser for both adults and children alike. So get those thinking caps on and see how many of these you can solve!
You can download the puzzle worksheet for numbers 1-100 here.
( Disclosure : Some of the links below are affiliate links, meaning, at no additional cost to you, I will earn a commission if you click through and make a purchase)
This book helps readers increase their ability to analyze data, calculate numbers, and develop a knowledge of how to solve mathematical problems, puzzles, trick questions, and riddles. There are 32 pages of this book are answers. The book makes it enjoyable to solve mathematical problems, including (multiplication addition division subtraction).
Have fun with a variety of mathematical pattern puzzles. The difficulty level gradually increases, starting off with easy patterns and easy problems. So, many of the patterns and problems in this book can be
Although these math puzzles seem difficult at first especially when you extend the activity for numbers up to 100, they can be quite fun and rewarding once you get the hang of them. And if you’re stuck, don’t hesitate to ask a friend or family member for help. After all, math is more enjoyable when it’s collaborative. So take your time, have fun, and Happy New Year!
Happy New Year 2023 everyone!
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Hi,
I assumed that the order must be preserved so the solution is
2023=17*7*17=(9+8)x7x(6+5+4+3-2+1)
Happy New Year, Jorge
So can it be done? It asks if you can do it “in that order?” But the solution has the numbers not descending 9-1…
Yes, here is one solution (9+8)x7x(6+5+4+3-2+1). One of the commentator has also given another solution.
I have a student who solved the math puzzle differently.
(9+8) x 7 x [{(6-5)+4} x 3 + (2×1)]
Great ! Thank you so much for sharing another solution to this problem.